Types of Covalent Bonding
Sigma Bonds (σ)
Every covalent bond includes exactly one σ-bond.
These bonds are formed when the electron cloud of two orbitals overlap directly between (in the center of) the two bonded atoms.
This can occur between s, p, and sp orbitals in any combination.
The electron density of the bond is concentrated between the two atoms.
σ-bonds are the strongest type of covalent bonds because of the direct overlapping of orbitals.
Pi Bonds (π)
π-bonds exist in double bonds (one σ-bond, one π-bond) and triple bonds (one σ-bond, two π-bond).
These bonds are formed when the electron cloud of two orbitals oriented perpendicular to the center overlap in a "side-by-side" manner.
This can occur between p and d orbitals.
The electron density of the bond is concentrated above and below the plane of the nuclei.
Because π-bonds involve indirect overlapping of orbitals, they are signficantly weaker than σ-bonds.
Bond Hybridization
If atoms can't bond together with their original electron configurations, they resolve to bond hybridization.
Bond hybridization is a concept used to explain molecular geometries. It introduces the idea that electron orbitals of bonded atoms combine to form "hybrid" orbitals that are equal in energy level and geometry.
This mechanism demonstrates how atoms can maximize bonding by reorganizing their orbitals.
How it Works
During hybridization, one s orbital and p orbital(s) combine to form hybrid orbitals, with the quantity depending on the type of hybridization (sp, sp², sp³).
Each hybrid orbital is asymmetrical in shape, with a smaller lobe (more s character) that points toward the nucleus, and a larger lobe (more p character) that points away from the nucleus.
sp hybridization - 1 s orbital + 1 p orbital, four electrons total. This creates one pair of sp orbitals, creating a linear electron geometry.
sp² hybridization - 1 s orbital + 2 p orbital, six electrons total. This creates three sp orbitals, creating a trigonal planar electron geometry.
sp³ hybridization - 1 s orbital + 3 p orbital, eight electrons total. This creates four sp orbitals, creating a tetrahedral electron geometry.
Example: Methane (CH₄)
A carbon atom has the electron configuration 1s², 2s², 2p². It needs four valence electrons to form four single bonds with hydrogen atoms to create methane, but only the two (unpaired) electrons of the 2p subshell are currently available.
First, one 2s electron jumps to an empty 2p orbital, creating the excited-state configuration of 1s², 2s¹, 2p³.
Next, the one 2s and three 2p orbitals undergo sp³ hybridization, forming four equivalent hybrid orbitals. These orbitals will automatically arrange to form a tetrahedral shape, and due to each of them possessing an unpaired electron, allow carbon to form σ-bonds with four hydrogen atoms by overlapping with their 1s orbitals.